Categories
discuss

Does Silverlight have a performance advantage over JavaScript?

At a recent discussion on Silverlight the advantage of speed was brought up. The argument for Silverlight was that it performed better in the browser than Javascript because it is compiled (and managed) code.

It was then stated that this advantage only applies to IE because IE interprets Javascript which is inefficient when compared to that of other browsers such as Chrome and FireFox which compile Javascript to machine code before execution and as such perform as well as Silverlight.

Does anybody have a definitive answer to this performance question. i.e. Do/will Silverlight and Javascript have comparable performance on Chrome and Firefox?

Answer

Speculating is fun. Or we could actually try a test or two…

That Silverlight vs. Javascript chess sample has been updated for Silverlight 2. When I run it, C# averages 420,000 nodes per second vs. Javascript at 23,000 nodes per second. I’m running the dev branch of Google Chrome (v. 0.4.154.25). That’s still almost an 18x speed advantage for Silverlight.

Primes calculation shows a 3x advantage for Silverlight: calculating 1,000,000 primes in Javascript takes 3.7 seconds, in Silverlight takes 1.2 seconds.

So I think that for calculation, there’s still a pretty strong advantage for Silverlight, and my gut feel is that it’s likely to stay that way. Both sides will continue to optimize, but there are some limits to what you can optimize in a dynamic language.

Silverlight doesn’t (yet) have an advantage when it comes to animation. For instance, the Bubblemark test shows Javascript running at 170 fps, and Silverlight running at 100 fps. I think we can expect to see that change when Silverlight 3 comes out, since it will include GPU support.

Categories
discuss

Bogus Eclipse warning for web.xml: “No grammar constraints (DTD or XML schema) detected for the document.”

The top of my web.xml file looks like this:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd"
    version="2.5">

But I still get the warning from Eclipse (Ganymede) that no XML schema is detected, and schema violations are not being warned about. Other XML files in my project (Spring Framework configuration files for example) don’t have the warning and do give correct warnings about schema violations.

How do I get the schema checking working and hopefully the warning to go away? The server does run correctly. It just appears to be an IDE issue.

Answer

Perhaps try:

http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd

Instead of:

http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd

Also, the <!DOCTYPE ...> is missing:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xml>
<web-app
  xmlns="http://java.sun.com/xml/ns/j2ee" 
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
  xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
  version="2.5">
  <!-- ... -->
</web-app>
Categories
discuss

Java dynamic binding and method overriding

Yesterday I had a two-hour technical phone interview (which I passed, woohoo!), but I completely muffed up the following question regarding dynamic binding in Java. And it’s doubly puzzling because I used to teach this concept to undergraduates when I was a TA a few years ago, so the prospect that I gave them misinformation is a little disturbing…

Here’s the problem I was given:

/* What is the output of the following program? */

public class Test {

  public boolean equals( Test other ) {
    System.out.println( "Inside of Test.equals" );
    return false;
  }

  public static void main( String [] args ) {
    Object t1 = new Test();
    Object t2 = new Test();
    Test t3 = new Test();
    Object o1 = new Object();

    int count = 0;
    System.out.println( count++ );// prints 0
    t1.equals( t2 ) ;
    System.out.println( count++ );// prints 1
    t1.equals( t3 );
    System.out.println( count++ );// prints 2
    t3.equals( o1 );
    System.out.println( count++ );// prints 3
    t3.equals(t3);
    System.out.println( count++ );// prints 4
    t3.equals(t2);
  }
}

I asserted that the output should have been two separate print statements from within the overridden equals() method: at t1.equals(t3) and t3.equals(t3). The latter case is obvious enough, and with the former case, even though t1 has a reference of type Object, it is instantiated as type Test, so dynamic binding should call the overridden form of the method.

Apparently not. My interviewer encouraged me to run the program myself, and lo and behold, there was only a single output from the overridden method: at the line t3.equals(t3).

My question then is, why? As I mentioned already, even though t1 is a reference of type Object (so static binding would invoke Object’s equals() method), dynamic binding should take care of invoking the most specific version of the method based on the instantiated type of the reference. What am I missing?

Answer

Java uses static binding for overloaded methods, and dynamic binding for overridden ones. In your example, the equals method is overloaded (has a different param type than Object.equals()), so the method called is bound to the reference type at compile time.

Some discussion here

The fact that it is the equals method is not really relevant, other than it is a common mistake to overload instead of override it, which you are already aware of based on your answer to the problem in the interview.

Edit: A good description here as well. This example is showing a similar problem related to the parameter type instead, but caused by the same issue.

I believe if the binding were actually dynamic, then any case where the caller and the parameter were an instance of Test would result in the overridden method being called. So t3.equals(o1) would be the only case that would not print.

Categories
discuss

How to set DPI information in an image?

I have an application that I want to export high-resolution (or rather, high pixel density?) images for printing – for example, I want images that print at 250 dots per inch (DPI), instead of the default, which I understand to be 72 DPI.

I’m using a BufferedImage with a Graphics2D object to draw the image, then ImageIO.write() to save the image.

Any idea how I can set the DPI?

Answer

Kurt’s answer showed the way, still it took me quite some time to get it run, so here is the code that sets DPI when saving a PNG. There is a lot to do to get the proper writers and such…

 private BufferedImage gridImage;
 ...

 private void saveGridImage(File output) throws IOException {
    output.delete();

    final String formatName = "png";

    for (Iterator<ImageWriter> iw = ImageIO.getImageWritersByFormatName(formatName); iw.hasNext();) {
       ImageWriter writer = iw.next();
       ImageWriteParam writeParam = writer.getDefaultWriteParam();
       ImageTypeSpecifier typeSpecifier = ImageTypeSpecifier.createFromBufferedImageType(BufferedImage.TYPE_INT_RGB);
       IIOMetadata metadata = writer.getDefaultImageMetadata(typeSpecifier, writeParam);
       if (metadata.isReadOnly() || !metadata.isStandardMetadataFormatSupported()) {
          continue;
       }

       setDPI(metadata);

       final ImageOutputStream stream = ImageIO.createImageOutputStream(output);
       try {
          writer.setOutput(stream);
          writer.write(metadata, new IIOImage(gridImage, null, metadata), writeParam);
       } finally {
          stream.close();
       }
       break;
    }
 }

 private void setDPI(IIOMetadata metadata) throws IIOInvalidTreeException {

    // for PMG, it's dots per millimeter
    double dotsPerMilli = 1.0 * DPI / 10 / INCH_2_CM;

    IIOMetadataNode horiz = new IIOMetadataNode("HorizontalPixelSize");
    horiz.setAttribute("value", Double.toString(dotsPerMilli));

    IIOMetadataNode vert = new IIOMetadataNode("VerticalPixelSize");
    vert.setAttribute("value", Double.toString(dotsPerMilli));

    IIOMetadataNode dim = new IIOMetadataNode("Dimension");
    dim.appendChild(horiz);
    dim.appendChild(vert);

    IIOMetadataNode root = new IIOMetadataNode("javax_imageio_1.0");
    root.appendChild(dim);

    metadata.mergeTree("javax_imageio_1.0", root);
 }
Categories
discuss

Event on a click everywhere on the page outside of the specific div

I’d like to hide a div when user click anywhere on the page outside of that div. How can I do that using raw javascript or jQuery?

Answer

Attach a click event to the document to hide the div:

$(document).click(function(e) {
   $('#somediv').hide();
});

Attach a click event to the div to stop clicks on it from propagating to the document:

$('#somediv').click(function(e) {
   e.stopPropagation();
});
Source: stackoverflow
Text is available under the Creative Commons Attribution-ShareAlike License; additional terms may apply. By using this site, you agree to the Privacy Policy, and Copyright Policy. Content is available under CC BY-SA 3.0 unless otherwise noted. The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 © No Copyrights, All Questions are retrived from public domain..